[SciPy-dev] ticket 464

[Alan G Isaac]

> Alan G Isaac wrote:
>>  That won't work.  A flattened matrix is still a matrix.
>>  But you can work with the flatiter representation.
>> 
>>      if max(x.shape) == 1: x = x.flat.next()


On Thu, 26 Jul 2007 20:30:58 +0300 dmitrey <openopt@ukr.net> apparently wrote:
> the matrix is converted to array before the check:
> So I had checked - it works


OK, I see.
But I still like the the above solution:
it's more general and in the context less confusing.
Or so I claim.  ;-)

Anyway, pick what you like.

Cheers,
Alan Isaac